Each entry of players should be able to claim the matching entry of rewards.
The constructor assigns with =, so a player listed twice keeps only the last reward. The earlier amount stays counted in remainingRewards but nobody can claim it. The duplicate also inflates i_players.length, which is the divisor in closePot.
Likelihood:
When a winner appears twice in the list, for example a player who won two prizes in one contest, or the admin builds the list by merging several result tables.
Impact:
The player receives only one of their rewards. The other stays in the Pot and is counted as "unclaimed" at closing.
The inflated i_players.length further reduces every claimant's bonus in closePot.
player1 is listed with 60 and 40 but can only claim 40. remainingRewards stays 60 after the claim.
The test uses the setup of the existing test/TestMyCut.t.sol.
Reject duplicates, or add the rewards together.
## Description The `for` loop inside the `Pot::constructor` override the `playersToRewards[i_players[i]]` with new reward `i_rewards[i]`.So if a player's address appears multiple times, the reward is overwritten rather than accumulated. This results in the player receiving only the reward from the last occurrence of their address in the array, ignoring prior rewards. ## Vulnerability Details **Proof of Concept:** 1. Suppose i_players contains \[0x123, 0x456, 0x123] and i_rewards contains \[100, 200, 300]. 2. The playersToRewards mapping will be updated as follows during construction: - For address 0x123 at index 0, reward is set to 300. - For address 0x456 at index 1, reward is set to 200. - For address 0x123 at index 2, reward is updated to 100. 3. As a result, the final reward for address 0x123 in playersToRewards will be 100, not 400 (300+100).This leads to incorrect and lower reward distributions. **Proof of Code (PoC):** place the following in the `TestMyCut.t.sol::TestMyCut` ```Solidity address player3 = makeAddr("player3"); address player4 = makeAddr("player4"); address player5 = makeAddr("player5"); address[] sixPlayersWithDuplicateOneAddress = [player1, player2, player3, player4, player1, player5]; uint256[] rewardForSixPlayers = [2, 3, 4, 5, 6, 7]; uint256 totalRewardForSixPlayers = 27; // 2+3+4+5+6+7 function test_ConstructorFailsInCorrectlyAssigningReward() public mintAndApproveTokens { for (uint256 i = 0; i < sixPlayersWithDuplicateOneAddress.length; i++) { console.log("Player: %s reward: %d", sixPlayersWithDuplicateOneAddress[i], rewardForSixPlayers[i]); } /** * player1 has two occurance in sixPlayersWithDuplicateOneAddress ( at index 0 and 4) * So it's expected reward should be 2+6 = 8 */ vm.startPrank(user); contest = ContestManager(conMan).createContest(sixPlayersWithDuplicateOneAddress, rewardForSixPlayers, IERC20(ERC20Mock(weth)), totalRewardForSixPlayers); ContestManager(conMan).fundContest(0); vm.stopPrank(); uint256 expectedRewardForPlayer1 = rewardForSixPlayers[0] + rewardForSixPlayers[4]; uint256 assignedRewardForPlaye1 = Pot(contest).checkCut(player1); console.log("Expected Reward For Player1: %d", expectedRewardForPlayer1); console.log("Assigned Reward For Player1: %d", assignedRewardForPlaye1); assert(assignedRewardForPlaye1 < expectedRewardForPlayer1); } ``` ## Impact The overall integrity of the reward distribution process is compromised. Players with multiple entries in the i_players\[] array will only receive the reward from their last occurrence in the array, leading to incorrect and lower reward distributions. ## Recommendations **Recommended Mitigation:** Aggregate the rewards for each player inside the constructor to ensure duplicate addresses accumulate rewards instead of overwriting them.This can be achieved by using the += operator in the loop that assigns rewards to players. ```diff for (uint256 i = 0; i < i_players.length; i++) { - playersToRewards[i_players[i]] = i_rewards[i]; + playersToRewards[i_players[i]] += i_rewards[i]; } ```
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