Puppy Raffle

AI First Flight #1
Beginner FriendlyFoundrySolidityNFT
EXP
View results
Submission Details
Severity: medium
Valid

Raffle Entry Can Be Permanently Blocked by Gas-Intensive Duplicate Checks

Root + Impact

Description

The enterRaffle function checks for duplicate players using nested loops that iterate over the entire players array.
As the number of players increases, this duplicate check becomes increasingly expensive because it runs in O(n²) time.

Since the players array grows over time and is fully user-controlled, an attacker can intentionally add many unique addresses to increase the gas cost of this loop. Eventually, calls to enterRaffle will exceed the block gas limit and revert, permanently preventing new players from entering the raffle and causing a Denial of Service.

// Check for duplicates
@> for (uint256 i = 0; i < players.length - 1; i++) {
@> for (uint256 j = i + 1; j < players.length; j++) {
@> require(
@> players[i] != players[j],
@> "PuppyRaffle: Duplicate player"
@> );
@> }
@> }
emit RaffleEnter(newPlayers);

Risk

Likelihood:

  • The players array grows every time enterRaffle is called, and the duplicate check is executed on every new entry, causing gas usage to increase continuously.

  • Any user can submit a large number of unique addresses through normal raffle participation, making the issue easy to trigger without special permissions.

Impact:

  • New players are eventually unable to enter the raffle because enterRaffle consistently reverts due to exceeding the block gas limit.

  • The raffle becomes permanently unusable, preventing the protocol from operating as intended and resulting in loss of availability.

Proof of Concept

contract DuplicateCheckDoSPoC {
PuppyRaffle raffle;
constructor(address raffleAddress) {
raffle = PuppyRaffle(raffleAddress);
}
function growPlayers(uint256 count) external payable {
address[] memory manyPlayers = new address[](count);
for (uint256 i = 0; i < count; i++) {
manyPlayers[i] = address(uint160(i + 1));
}
raffle.enterRaffle{value: raffle.entranceFee() * count}(manyPlayers);
}
}

Recommended Mitigation

- // Check for duplicates
- for (uint256 i = 0; i < players.length - 1; i++) {
- for (uint256 j = i + 1; j < players.length; j++) {
- require(
- players[i] != players[j],
- "PuppyRaffle: Duplicate player"
- );
- }
- }
+ mapping(address => bool) public hasEntered;
+ for (uint256 i = 0; i < newPlayers.length; i++) {
+ require(!hasEntered[newPlayers[i]], "PuppyRaffle: Duplicate player");
+ hasEntered[newPlayers[i]] = true;
+ players.push(newPlayers[i]);
+ }
Updates

Lead Judging Commences

ai-first-flight-judge Lead Judge about 6 hours ago
Submission Judgement Published
Validated
Assigned finding tags:

[M-01] `PuppyRaffle: enterRaffle` Use of gas extensive duplicate check leads to Denial of Service, making subsequent participants to spend much more gas than prev ones to enter

## Description `enterRaffle` function uses gas inefficient duplicate check that causes leads to Denial of Service, making subsequent participants to spend much more gas than previous users to enter. ## Vulnerability Details In the `enterRaffle` function, to check duplicates, it loops through the `players` array. As the `player` array grows, it will make more checks, which leads the later user to pay more gas than the earlier one. More users in the Raffle, more checks a user have to make leads to pay more gas. ## Impact As the arrays grows significantly over time, it will make the function unusable due to block gas limit. This is not a fair approach and lead to bad user experience. ## POC In existing test suit, add this test to see the difference b/w gas for users. once added run `forge test --match-test testEnterRaffleIsGasInefficient -vvvvv` in terminal. you will be able to see logs in terminal. ```solidity function testEnterRaffleIsGasInefficient() public { vm.startPrank(owner); vm.txGasPrice(1); /// First we enter 100 participants uint256 firstBatch = 100; address[] memory firstBatchPlayers = new address[](firstBatch); for(uint256 i = 0; i < firstBatchPlayers; i++) { firstBatch[i] = address(i); } uint256 gasStart = gasleft(); puppyRaffle.enterRaffle{value: entranceFee * firstBatch}(firstBatchPlayers); uint256 gasEnd = gasleft(); uint256 gasUsedForFirstBatch = (gasStart - gasEnd) * txPrice; console.log("Gas cost of the first 100 partipants is:", gasUsedForFirstBatch); /// Now we enter 100 more participants uint256 secondBatch = 200; address[] memory secondBatchPlayers = new address[](secondBatch); for(uint256 i = 100; i < secondBatchPlayers; i++) { secondBatch[i] = address(i); } gasStart = gasleft(); puppyRaffle.enterRaffle{value: entranceFee * secondBatch}(secondBatchPlayers); gasEnd = gasleft(); uint256 gasUsedForSecondBatch = (gasStart - gasEnd) * txPrice; console.log("Gas cost of the next 100 participant is:", gasUsedForSecondBatch); vm.stopPrank(owner); } ``` ## Recommendations Here are some of recommendations, any one of that can be used to mitigate this risk. 1. User a mapping to check duplicates. For this approach you to declare a variable `uint256 raffleID`, that way each raffle will have unique id. Add a mapping from player address to raffle id to keep of users for particular round. ```diff + uint256 public raffleID; + mapping (address => uint256) public usersToRaffleId; . . function enterRaffle(address[] memory newPlayers) public payable { require(msg.value == entranceFee * newPlayers.length, "PuppyRaffle: Must send enough to enter raffle"); for (uint256 i = 0; i < newPlayers.length; i++) { players.push(newPlayers[i]); + usersToRaffleId[newPlayers[i]] = true; } // Check for duplicates + for (uint256 i = 0; i < newPlayers.length; i++){ + require(usersToRaffleId[i] != raffleID, "PuppyRaffle: Already a participant"); - for (uint256 i = 0; i < players.length - 1; i++) { - for (uint256 j = i + 1; j < players.length; j++) { - require(players[i] != players[j], "PuppyRaffle: Duplicate player"); - } } emit RaffleEnter(newPlayers); } . . . function selectWinner() external { //Existing code + raffleID = raffleID + 1; } ``` 2. Allow duplicates participants, As technically you can't stop people participants more than once. As players can use new address to enter. ```solidity function enterRaffle(address[] memory newPlayers) public payable { require(msg.value == entranceFee * newPlayers.length, "PuppyRaffle: Must send enough to enter raffle"); for (uint256 i = 0; i < newPlayers.length; i++) { players.push(newPlayers[i]); } emit RaffleEnter(newPlayers); } ```

Support

FAQs

Can't find an answer? Chat with us on Discord, Twitter or Linkedin.

Give us feedback!