Puppy Raffle

AI First Flight #1
Beginner FriendlyFoundrySolidityNFT
EXP
View results
Submission Details
Severity: medium
Valid

[L] In enterRaffle, when the array is very large, the algorithm for checking duplicate players is O(n^2), which can lead to excessively high gas and transaction failure.

Root + Impact

Description

  • Users may call the enterRaffle method with an array to register for the raffle.

  • When users pass an excessively large array to enterRaffle, it can cause the gas fee to exceed the limit, resulting in transaction failure.

// Root cause in the codebase with @> marks to highlight the relevant section
function enterRaffle(address[] memory newPlayers) public payable {
//@> Double-loop de-duplication consumes a great deal of gas.
for (uint256 i = 0; i < players.length - 1; i++) {
for (uint256 j = i + 1; j < players.length; j++) {
require(players[i] != players[j], "PuppyRaffle: Duplicate player");
}
}
}

Risk

Likelihood:

  • The array is too large, and the nested loops are very inefficient, consuming a great deal of gas.

  • If the array is too large, gas consumption can reach the limit and cause the transaction to fail.

Impact:

  • High gas consumption

  • Low algorithm efficiency

Proof of Concept

  1. Simulate 1000 players entering the raffle

  2. Use custom:gas-limit 16000000 to test: forge test --mt test_Poc_EnterRaffleGasLimit --block-gas-limit 16000000 --enable-tx-gas-limit -vv

function test_Poc_EnterRaffleGasLimit() public {
// 1. Simulate 1000 players entering the raffle, each paying entranceFee
address[] memory players = new address[](1000);
for (uint256 i = 0; i < 1000; i++) {
players[i] = address(i + 1);
}
vm.expectRevert();
puppyRaffle.enterRaffle{value: entranceFee * 1000}(players);
}

Recommended Mitigation

  1. Use mapping to record the players

  2. Use mapping to deduplicate an array


+ mapping(address => bool) public hasEntered;
function enterRaffle(address[] memory newPlayers) public payable {
for (uint256 i = 0; i < newPlayers.length; i++) {
+ require(!hasEntered[newPlayers[i]], "PuppyRaffle: Duplicate player");
players.push(newPlayers[i]);
+ hasEntered[newPlayers[i]] = true;
}
}
function _isActivePlayer() internal view returns (bool) {
+ if (hasEntered[msg.sender]) {
+ return true;
+ }
- for (uint256 i = 0; i < players.length; i++) {
- if (players[i] == msg.sender) {
- return true;
- }
- }
}
function refund(uint256 playerIndex) public {
+ hasEntered[playerAddress] = false;
}
function selectWinner() external {
+ for(uint256 i = 0; i < players.length; i++) {
+ hasEntered[players[i]] = false;
+ }
delete players;
}
Updates

Lead Judging Commences

ai-first-flight-judge Lead Judge about 3 hours ago
Submission Judgement Published
Validated
Assigned finding tags:

[M-01] `PuppyRaffle: enterRaffle` Use of gas extensive duplicate check leads to Denial of Service, making subsequent participants to spend much more gas than prev ones to enter

## Description `enterRaffle` function uses gas inefficient duplicate check that causes leads to Denial of Service, making subsequent participants to spend much more gas than previous users to enter. ## Vulnerability Details In the `enterRaffle` function, to check duplicates, it loops through the `players` array. As the `player` array grows, it will make more checks, which leads the later user to pay more gas than the earlier one. More users in the Raffle, more checks a user have to make leads to pay more gas. ## Impact As the arrays grows significantly over time, it will make the function unusable due to block gas limit. This is not a fair approach and lead to bad user experience. ## POC In existing test suit, add this test to see the difference b/w gas for users. once added run `forge test --match-test testEnterRaffleIsGasInefficient -vvvvv` in terminal. you will be able to see logs in terminal. ```solidity function testEnterRaffleIsGasInefficient() public { vm.startPrank(owner); vm.txGasPrice(1); /// First we enter 100 participants uint256 firstBatch = 100; address[] memory firstBatchPlayers = new address[](firstBatch); for(uint256 i = 0; i < firstBatchPlayers; i++) { firstBatch[i] = address(i); } uint256 gasStart = gasleft(); puppyRaffle.enterRaffle{value: entranceFee * firstBatch}(firstBatchPlayers); uint256 gasEnd = gasleft(); uint256 gasUsedForFirstBatch = (gasStart - gasEnd) * txPrice; console.log("Gas cost of the first 100 partipants is:", gasUsedForFirstBatch); /// Now we enter 100 more participants uint256 secondBatch = 200; address[] memory secondBatchPlayers = new address[](secondBatch); for(uint256 i = 100; i < secondBatchPlayers; i++) { secondBatch[i] = address(i); } gasStart = gasleft(); puppyRaffle.enterRaffle{value: entranceFee * secondBatch}(secondBatchPlayers); gasEnd = gasleft(); uint256 gasUsedForSecondBatch = (gasStart - gasEnd) * txPrice; console.log("Gas cost of the next 100 participant is:", gasUsedForSecondBatch); vm.stopPrank(owner); } ``` ## Recommendations Here are some of recommendations, any one of that can be used to mitigate this risk. 1. User a mapping to check duplicates. For this approach you to declare a variable `uint256 raffleID`, that way each raffle will have unique id. Add a mapping from player address to raffle id to keep of users for particular round. ```diff + uint256 public raffleID; + mapping (address => uint256) public usersToRaffleId; . . function enterRaffle(address[] memory newPlayers) public payable { require(msg.value == entranceFee * newPlayers.length, "PuppyRaffle: Must send enough to enter raffle"); for (uint256 i = 0; i < newPlayers.length; i++) { players.push(newPlayers[i]); + usersToRaffleId[newPlayers[i]] = true; } // Check for duplicates + for (uint256 i = 0; i < newPlayers.length; i++){ + require(usersToRaffleId[i] != raffleID, "PuppyRaffle: Already a participant"); - for (uint256 i = 0; i < players.length - 1; i++) { - for (uint256 j = i + 1; j < players.length; j++) { - require(players[i] != players[j], "PuppyRaffle: Duplicate player"); - } } emit RaffleEnter(newPlayers); } . . . function selectWinner() external { //Existing code + raffleID = raffleID + 1; } ``` 2. Allow duplicates participants, As technically you can't stop people participants more than once. As players can use new address to enter. ```solidity function enterRaffle(address[] memory newPlayers) public payable { require(msg.value == entranceFee * newPlayers.length, "PuppyRaffle: Must send enough to enter raffle"); for (uint256 i = 0; i < newPlayers.length; i++) { players.push(newPlayers[i]); } emit RaffleEnter(newPlayers); } ```

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