sendToL1()
parses an arbitrary set of bytes to obtain address target
.
This value is then used in a call()
.
However it is possible for target == address(0)
, which would result in the value sent with the call()
being lost.
address(0).call()
will always succeed, and the funds will be burned.
Loss of funds.
Manual inspection.
Revert with an error if target == address(0)
before executing target.call()
.
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