Puppy Raffle

AI First Flight #1
Beginner FriendlyFoundrySolidityNFT
EXP
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Submission Details
Severity: medium
Valid

✅Looping through that player array to check for duplicates in `PuppyRaffle::enterRaffle` is a potential denial of service (DoS) attack, incrementing gas costs for future entrants

Root + Impact: Looping through that player array to check for duplicates in PuppyRaffle::enterRaffle is a potential denial of service (DoS) attack, incrementing gas costs for future entrants

Description

The `PuppyRaffle::enterRaffle` function loops through the `players` array to check for duplicates. However, the longer the `PuppyRaffle::players` array is, the more checks a new player will have to make. This means the gas costs for players who enter right when the raffle starts will be dramatically lower than those who enter later. Every additional address in the `players` array, is an additional check the loop will have to make.
```javascript
@> for (uint256 i = 0; i < players.length - 1; i++) {
for (uint256 j = i + 1; j < players.length; j++) {
require(players[i] != players[j], "PuppyRaffle: Duplicate player");
}
}
```

Impact:

The gas cost for raffle entrants will greatly increase as more players enter the rafle. Discouraging later users from enterring, and causing a rush at the start of a raffle to be one of the first entrants in the queeue.
An attacker might make the `PuppyRaffle::entrants` array so big, that no one else enters, guarenteeing themselves the win.

Proof of Concept

If we have 2 sets of 100 players enter, the gas costs will be as such:
- 1st 100 players: ~6503275 gas
- 2nd 100 players: ~18995515 gas
This is more than 3x more expensive for the second 100 players.
<details>
<summary>PoC</summary>
Place the following test into `PuppyRaffleTest.t.sol`.
```javascript
function test_For_DOS() public {
uint256 playersNum = 100;
address[] memory players = new address[](playersNum);
for(uint256 i = 0; i < playersNum; i++) {
players[i] = address(i);
}
// see gas
uint256 gasStart = gasleft();
puppyRaffle.enterRaffle{value: entranceFee * players.length}(players);
uint256 gasEnd = gasleft();
uint256 gasUsedFirst = (gasStart - gasEnd);
console.log("Gas used of the first 100 players: ", gasUsedFirst);
// Players for the second 100 players
address[] memory playersTwo = new address[](playersNum);
for(uint256 i = 0; i < playersNum; i++) {
playersTwo[i] = address(i + playersNum); // 101, 102
}
// see gas
uint256 gasStartSecond = gasleft();
puppyRaffle.enterRaffle{value: entranceFee * players.length}(playersTwo);
uint256 gasEndSecond = gasleft();
uint256 gasUsedSecond = (gasStartSecond - gasEndSecond);
console.log("Gas used of the first 100 players: ", gasUsedSecond);
assert(gasUsedFirst < gasUsedSecond);
}
```
</details>

Recommended Mitigation

There are a few recommedations.
1. Consider allowing duplicates. Users can make new wallets addresses anyways, so a duplicate check doesn't prevent thesame person from entering multiple times, only thesame wallet address.
2. Consider using a mapping to check for duplicates. This would allow constant time lookup of whether a user has already entered.
```diff
+ mapping(address => uint256) public addressToRaffleId;
+ uint256 public raffleId = 0;
.
.
.
function enterRaffle(address[] memory newPlayers) public payable {
require(msg.value == entranceFee * newPlayers.length, "PuppyRaffle: Must send enough to enter raffle");
for (uint256 i = 0; i < newPlayers.length; i++) {
players.push(newPlayers[i]);
+ addressToRaffleId[newPlayers[i]] = raffleId;
}
- // Check for duplicates
+ // Check for duplicates only from the new players
+ for (uint256 i = 0; i < newPlayers.length; i++) {
+ require(addressToRaffleId[newPlayers[i]] != raffleId, "PuppyRaffle: Duplicate player");
+ }
- for (uint256 i = 0; i < players.length; i++) {
- for (uint256 j = i + 1; j < players.length; j++) {
- require(players[i] != players[j], "PuppyRaffle: Duplicate player");
- }
- }
emit RaffleEnter(newPlayers);
}
.
.
.
function selectWinner() external {
+ raffleId = raffleId + 1;
require(block.timestamp >= raffleStartTime + raffleDuration, "PuppyRaffle: Raffle not over");
}
```
3. Alternatively, you could use [Openzeppelin's `EnumerableSet` library]
Updates

Lead Judging Commences

ai-first-flight-judge Lead Judge about 3 hours ago
Submission Judgement Published
Validated
Assigned finding tags:

[M-01] `PuppyRaffle: enterRaffle` Use of gas extensive duplicate check leads to Denial of Service, making subsequent participants to spend much more gas than prev ones to enter

## Description `enterRaffle` function uses gas inefficient duplicate check that causes leads to Denial of Service, making subsequent participants to spend much more gas than previous users to enter. ## Vulnerability Details In the `enterRaffle` function, to check duplicates, it loops through the `players` array. As the `player` array grows, it will make more checks, which leads the later user to pay more gas than the earlier one. More users in the Raffle, more checks a user have to make leads to pay more gas. ## Impact As the arrays grows significantly over time, it will make the function unusable due to block gas limit. This is not a fair approach and lead to bad user experience. ## POC In existing test suit, add this test to see the difference b/w gas for users. once added run `forge test --match-test testEnterRaffleIsGasInefficient -vvvvv` in terminal. you will be able to see logs in terminal. ```solidity function testEnterRaffleIsGasInefficient() public { vm.startPrank(owner); vm.txGasPrice(1); /// First we enter 100 participants uint256 firstBatch = 100; address[] memory firstBatchPlayers = new address[](firstBatch); for(uint256 i = 0; i < firstBatchPlayers; i++) { firstBatch[i] = address(i); } uint256 gasStart = gasleft(); puppyRaffle.enterRaffle{value: entranceFee * firstBatch}(firstBatchPlayers); uint256 gasEnd = gasleft(); uint256 gasUsedForFirstBatch = (gasStart - gasEnd) * txPrice; console.log("Gas cost of the first 100 partipants is:", gasUsedForFirstBatch); /// Now we enter 100 more participants uint256 secondBatch = 200; address[] memory secondBatchPlayers = new address[](secondBatch); for(uint256 i = 100; i < secondBatchPlayers; i++) { secondBatch[i] = address(i); } gasStart = gasleft(); puppyRaffle.enterRaffle{value: entranceFee * secondBatch}(secondBatchPlayers); gasEnd = gasleft(); uint256 gasUsedForSecondBatch = (gasStart - gasEnd) * txPrice; console.log("Gas cost of the next 100 participant is:", gasUsedForSecondBatch); vm.stopPrank(owner); } ``` ## Recommendations Here are some of recommendations, any one of that can be used to mitigate this risk. 1. User a mapping to check duplicates. For this approach you to declare a variable `uint256 raffleID`, that way each raffle will have unique id. Add a mapping from player address to raffle id to keep of users for particular round. ```diff + uint256 public raffleID; + mapping (address => uint256) public usersToRaffleId; . . function enterRaffle(address[] memory newPlayers) public payable { require(msg.value == entranceFee * newPlayers.length, "PuppyRaffle: Must send enough to enter raffle"); for (uint256 i = 0; i < newPlayers.length; i++) { players.push(newPlayers[i]); + usersToRaffleId[newPlayers[i]] = true; } // Check for duplicates + for (uint256 i = 0; i < newPlayers.length; i++){ + require(usersToRaffleId[i] != raffleID, "PuppyRaffle: Already a participant"); - for (uint256 i = 0; i < players.length - 1; i++) { - for (uint256 j = i + 1; j < players.length; j++) { - require(players[i] != players[j], "PuppyRaffle: Duplicate player"); - } } emit RaffleEnter(newPlayers); } . . . function selectWinner() external { //Existing code + raffleID = raffleID + 1; } ``` 2. Allow duplicates participants, As technically you can't stop people participants more than once. As players can use new address to enter. ```solidity function enterRaffle(address[] memory newPlayers) public payable { require(msg.value == entranceFee * newPlayers.length, "PuppyRaffle: Must send enough to enter raffle"); for (uint256 i = 0; i < newPlayers.length; i++) { players.push(newPlayers[i]); } emit RaffleEnter(newPlayers); } ```

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